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161x^2+283x-37=0
a = 161; b = 283; c = -37;
Δ = b2-4ac
Δ = 2832-4·161·(-37)
Δ = 103917
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(283)-\sqrt{103917}}{2*161}=\frac{-283-\sqrt{103917}}{322} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(283)+\sqrt{103917}}{2*161}=\frac{-283+\sqrt{103917}}{322} $
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